6w+w^2-600=0

Solution for 6w+w^2-600=0 equation:

6w+w^2-600=0

a = 1; b = 6; c = -600;
Δ = b2-4ac
Δ = 62-4·1·(-600)
Δ = 2436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2436}=\sqrt{4*609}=\sqrt{4}*\sqrt{609}=2\sqrt{609}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{609}}{2*1}=\frac{-6-2\sqrt{609}}{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{609}}{2*1}=\frac{-6+2\sqrt{609}}{2}
$